An astronaut whose height is 1.50 m floats "feet down" in an orbiting space shuttle at a distance 
away from the center of Earth. The magnitude of difference between the gravitational acceleration at her feet and at her head is found to be N x 10 -6 m s -2 . What is the value of N?
[M E = 6 x 10 24 kg and G = 6.67 x 10 -11 N m 2 kg -2 ]
Text Solution
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CHECK THE SOLUTION.
(1.8 )
The gravitational acceleration at any distance r from the center of Earth is 
. On differentiating,
we get 
, where dais infinitesimal change in a due to differential change dr in r.
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